**Your
answer to Q185: **Sorry,
your answer is **not **correct.

Help: *Fundamentals of
Sound*, Chap. 5-A.

Or, would you like a HINT?

You should really try to work out the answer on your own, but if you insist on reading it, the correct answer is HERE.

Return to Question
185.

**Hint
for Q185**: You could use the formula* I=I*_{0}(*R*_{0}/*R*)^{2},
but you have to understand what that means, of course. The intensity is proportional
to the **square** of the distance, not just to the distance.

Return to Question 185.

**Your
answer to Q185: **Congratulations, your answer is **correct**!

To read the "official" correct answer, click HERE.

Return
to Question 185.

**Correct
answer to Q185**: The intensity falls off as the square of the distance.
Thus if the distance is twice as far, as it is here (100/50 = 2), the intensity
is* *1/2^{2} = 1/4 times as much. Since(0.08 W/m^{2})/4=0.02
W/m^{2}, the answer is e).

Return
to Question 185.

**Your
answer to Q187: **Sorry, your answer is **not **correct.

Help: *Fundamentals of
Sound*, Chap. 5-A.

Or, would you like a HINT?

You should really try to work out the answer on your own, but if you insist on reading it, the correct answer is HERE.

Return to Question
187.

**Hint
for Q187**: You could use the formula I=I_{0}(R_{0}/R)^{2},
but you have to understand what that means, of course. The intensity is proportional
to the **square** of the distance, not just to the distance.

Return to Question 187.

**Your
answer to Q187: **Congratulations, your answer is **correct**!

To read the "official" correct answer, click HERE.

Return
to Question 187.

**Correct
answer to Q187**: The intensity changes as the square of the distance.
Thus, if the distance is three times closer, as it is here (60/20 = 3), the
intensity is 3^{2} = 9 times as much. Since 0.09x9=0.81 W/m^{2},
the answer is a).

Return
to Question 187.

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