**Correct
Answer to Question 450:**
b) is correct. In this calculation you add exponents:10^{2} x 10^{4}=10^{(2+4)}=10^{6}.

Help: *Fundamentals of
Sound*, Sec. 10-L.

Return to Question 450.

**Correct
Answer to Question 455:** c) is correct. To move the decimal one place
to the left you increase the exponent by 1. 36.7 x 10^{5}=3.67 x 10
x 10^{5}=3.67 x 10^{1} x 10^{5}=3.67 x 10^{6}

Help: *Fundamentals of
Sound*, Sec. 10-J.

Return to Question 455.

**Correct
Answer to Question 460:** c) is correct. To move the decimal one place
to the right you add -1 to the exponent. 0.283 x 10^{-6}=2.83 x (1/10)
x 10^{-6}= 2.83 x 10^{-1} x 10^{-6}=2.83 x 10^{-7}

Help: *Fundamentals of
Sound*, Sec. 10-J.

Return to Question 460.

**Correct
Answer to Question 465:** a) is correct. To divide one power of ten by another
you subtract the exponent in the denominator from that in the numerator. 10^{-2}/10^{-6}=
10^{-2-(-6)}= 10^{-2+6} = 10^{4}

Help: *Fundamentals of
Sound*, Sec. 10-L.

Return to Question 465.

**Correct
Answer to Question 470:** c) is correct. To add numbers with different
powers of ten you must put both into the same power of ten. One way is to write
8 x 10^{6} =0.8 x 10^{7}. Now both numbers have the same power
of ten. Simply add the numbers:

7 x 10^{7}

-0.8 x 10^{7}

_________

6.2 x 10^{7}

Help: *Fundamentals of
Sound*, Sec. 10-K.

Return to Question 470.

**Correct
Answer to Question 472:** d) is correct. To add numbers with different powers
of ten you must put both into the same power of ten. You might write 0.3 x 10^{-1}
= 30 x 10^{-3}. Now both numbers have the same power of ten. Simply
add the numbers:

5 x 10^{-3}

30 x 10^{-3}

_________

35 x 10^{-3}.

This last number is equivalent
to 3.5 x 10^{-2}.

Help: *Fundamentals of
Sound*, Sec. 10-K.

Return to Question 472.

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